如下面的帮助示例代码：怎样设计成通用的导出窗口呢？表名和保存文件名都可以指定的那种。

设计方法很简单：

1、将窗口的AfterLoad事件代码设置为：

Dim ckl As WinForm.CheckedListBox = e.Form.Controls("CheckedListBox1")
For Each dc As DataCol In DataTables("订单").DataCols
    ckl.Items.Add(dc.name)
Next

2、将导出按钮的Clik事件代码设置为：

Dim ckl As WinForm.CheckedListBox = e.Form.Controls("CheckedListBox1")
Dim nms As New List(of String)
For i As Integer = 0 To ckl.Items.count - 1 \'获取已经勾选的列
    If ckl.GetItemChecked(i) Then
        nms.Add(ckl.Items(i))
    End If
Next
If nms.Count = 0 Then
    MessageBox.Show("至少要选择一列","提示",MessageBoxButtons.OK,MessageBoxIcon.Information)
    Return
End If 
\'生成Excel表
Dim dt As Table = Tables("订单")
Dim Book As New XLS.Book
Dim Sheet As XLS.Sheet = Book.Sheets(0)
For i As Integer = 0 To nms.count -1
    Sheet(0, i).Value = nms(i)
Next
For r As Integer = 0 To dt.Rows.Count - 1 \'填入数据
    For i As Integer = 0 To nms.count -1
        Sheet(r + 1, i).Value = dt.rows(r)(nms(i))
    Next
Next 
\'保存并打开excel文件
Book.Save("c:\\reports\\test.xls")
Dim Proc As New Process
Proc.File = "c:\\reports\\test.xls"
Proc.Start()

你可以用全局变量，比如你打开窗口前赋值

vars("表名") = Tables("表A")

然后在代码里面，就用 vars("表名") 代替 Tables("订单")