说明书上取userid的例子，从逻辑上来说，有可能出现当第一次点击菜单时，通过code与e.Cookies("userid")取不到userid .这样进入授权链接。只有当再次点击菜单时，才能取出userid.这样会用户一个错觉，认为网打不开，或没有数据，因为没有userid时，就得不到这个人的相关权限。有没有更好的方法，点击一次就能取到userid呢？
If e.host = "wexin.foxtable.com" Then '需要授权才能访问的域名
Dim UserId As String
Dim UserName
As String
Dim sb As New StringBuilder
sb.AppendLine("<meta
name='viewport'
c>")
If e.GetValues.ContainsKey("code") Then
'如果通过授权链接跳转而来,就根据传递过来的code参数调用接口,获取用户的UserId
Dim ul As String =
"https://qyapi.weixin.qq.com/cgi-bin/user/getuserinfo?access_token={0}&code={1}"
ul = CExp(ul,Functions.Execute("GetQYAccessToken"),e.GetValues("code"))
Dim hc As new HttpClient(ul)
Dim
jo As JObject = JObject.Parse(hc.GetData)
If jo("UserId") IsNot
Nothing Then
UserId = jo("UserId")
End If
Else
UserId = e.Cookies("userid")
'否则从cookie中提取userid和username
End If
Dim Verified As Boolean
Dim dr As DataRow =
DataTables("Users").Find("userid ='"
& UserId &
"'") '根据openid找出对应的行
If UserId > ""
AndAlso dr
IsNot Nothing
AndAlso dr("permit") =
True '授权成功
Verified = True
UserName = dr("name")
e.AppendCookie("userid",UserId)
'将userid和username存储在Cookie中
ElseIf e.GetValues.ContainsKey("code") = False
Then '如果授权失败,且不是通过授权链接跳转而来,那么就跳转到授权链接
Dim ul As String = "https://open.weixin.qq.com/connect/oauth2/authorize?appid=wxa31aba4cd83af57e&redirect_uri=http%3a%2f%2fwexin.foxtable.com&response_type=code&scope=snsapi_base&state=123#wechat_redirect"
sb.Append("<meta
http-equiv='Refresh' c>")
'跳转到授权链接
e.WriteString(sb.ToString)
Return
End
If
If
Verified = False Then
sb.AppendLine("你无权访问本系统")
Else
sb.AppendLine("欢迎" & UserName
& " , <a href='http://wexin.foxtable.com'>刷新页面</a>")
End If
e.WriteString(sb.ToString)
End If
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Post By：2019/4/26 15:49:00 [只看该作者]
