主题：[求助]动态生成网页怎么获取数据库的数据

但是额

怎么才能在我点击筛选按钮后提交数据，但是不跳转到result.html页面呢？？

With wb.AddButtonGroup("form1","btg1",True)

            .Add("btnok","筛选","button").Attribute = ""    我想在这里点击筛选按钮调用会话框dlg1

        End With

        With wb.AddDialog("","dlg1","提示","筛选成功")

            .AddButton("btnOK","OK")

        End With

js代码：function myfunction(){

    var result = submitAjaxForm('form1','',false);

show('dlg1');

    }

我js该怎么写呢

Select Case e.Path

    Case "filter.html"

        wb.AddForm("","form1","result.html")

        With wb.AddInputGroup("form1","ipg1","日报表筛选")

            .AddSelect("Name","姓名",dtb.SQLGetComboListString("姓名")) '这里的Name会自动转换为小写name

            .AddInput("StartDate","开始日期","date")

            .AddInput("EndDate","结束日期","date")

        End With

        With wb.AddButtonGroup("form1","btg1",True)

            .Add("btnok","筛选","button").Attribute = ""

        End With

        With wb.AddDialog("","dlg1","提示","筛选成功")

            .AddButton("btnOK","OK")

        End With

        wb.AppendHTML("<script src='./lib/ajaxform.js'></script>") '引入脚本文件

        e.WriteString(wb.Build)

这样能看出问题在哪么？